tolong dong,pake cara yaa
a. 1,25
Pembahasan
[tex]\begin{aligned}{\sf{2-\dfrac{1}{2-\frac{1}{2-\frac{1}{2}}}}}&={\sf{2-\dfrac{1}{2-\frac{1}{\frac{4}{2}-\frac{1}{2}}}}}\\&={\sf{2-\dfrac{1}{2-\frac{1}{\frac{3}{2}}}}}\\&={\sf{2-\dfrac{1}{2-\frac{1\times2}{3}}}}\\&={\sf{2-\dfrac{1}{2-\frac{2}{3}}}}\\&={\sf{2-\dfrac{1}{\frac{6}{3}-\frac{2}{3}}}}\\&={\sf{2-\dfrac{1}{\frac{4}{3}}}}\\&={\sf{2-\dfrac{1\times3}{4}}}\\&={\sf{2-\dfrac{3}{4}}}\\&={\sf{\dfrac{8}{4}-\dfrac{3}{4}}}\\&={\sf{\dfrac{5}{4}}}\\&={\sf{1,25}}\end{aligned}[/tex]
[answer.2.content]
